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    1. #1
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      Mặc định Nguyên lý máy hàn (tôi) cao tần.

      Chào các bạn, trong công nghiệp hiện nay có rất nhiều loại máy tôi, hàn sử dụng dải tần số cao để tạo ra nhiệt độ tác động trực tiếp lên bề mặt vật liệu cần nung, hàn. Với những ưu điểm sau:
      - Nung chảy kim loại, nung nóng kim loại trong lĩnh vực gia công, tôi toàn bộ chi tiết hoặc từng phần của chi tiết.
      - Cho phép thay đổi công suất nung, thời gian nung chính xác trong việc gia công kim loại, thời gian nung nhanh và nhiệt độ cho phép đạt được lên tới 1.6000C
      - Ứng dụng trong lĩnh vực luyện, nấy chảy quặng như: Quặng vàng, bạc, đồng, nhôm, thép và những kim loại quí khác.
      - Làm khô nhanh bề mặt vật liệu.
      - Ứng dụng trong lĩnh vực tôi kim loại như: Đầu mũi khoan lớn, dao, những dụng cụ gia công cơ khí,...
      - Ứng dụng trong nhà máy hàn ống thép.



      Để tiện thảo luận tôi xin trích dẫn bài viết Induction Heater Tutorial 10kw and 3kw vào topic này.

      Induction Heater Tutorial
      10kw and 3kw

      Disclaimer: The topics discussed use high voltage and heat. They can cause property damage as well as hurt and kill. This site and author have made this information public for educational purposes only. Anyone who reads this and attempts to make a device based on any part of it does so at his/her own risk. This is disavows any responsibility, and does not encourage anyone to do this.

      An induction heater is an interesting device, allowing one to rapidly heat a metal object. With enough power, one can even melt metal. The induction heater works without the need for fossil fuels, and can anneal and heat objects of various shapes. I set out to make an induction heater that could melt steel and aluminum. So far I have been able to feed an input power of over 3 kilowatts! Now that I have done this I would like to share how it works, and how you can build one. At the end of the tutorial I will discuss and show you how to build a levitation coil that will allow you to boil metals while suspended in mid air!

      The first part of this tutorial will go through my development of a 3kw inverter. My initial goal was to rapidly heat metals. My next goal was to levitate metals. I succeeded, but realized that I could not levitate solid copper and steel. Their density was too great for the magnetic field. This was my final goal: to levitate and suspend molten copper and steel. At the end of this tutorial I will go into the development of a 10kw unit that realized this goal. I will also elaborate on the problems that had to be overcome in order to achieve this.

      Let's start.

      My induction heater is an inverter. An inverter takes a DC power source and converts it into AC power. The AC power drives a transformer which is coupled to a series LC tank. The inverter frequency is set to the tank's resonant frequency, allowing the generation of very high currents within the tank's coil. The coil is coupled to the workpiece and sets up eddy currents. These currents, traveling through a conductive, but slightly resistive workpiece, heat the piece. Remember, Power = Heat = R*I^2. The workpiece is like a one-turn coil; the work coils has several turns. Thus, we have a step-down transformer, so even higher currents are generated in the workpiece.

      I would like to acknowledge the invaluable help from John Dearmond, Tim Williams, Richie Burnett and other members of the 4hv forum for helping me understand this topic. Now, before we talk more, let's see some pictures of what it can do:

      Later, I will give a link to a video showing it running. Here is the inverter:

      What I will now do is go over each part. Then, I will give the schematics, go over them and how you can build this device
      Induction Heater Components

      We will talk about each component making up the induction heater. First, there is the workcoil. This is what heats the workpiece. The workcoil will get very hot from the high current going through it and the radiation of heat from the workpiece.

      The workcoil is attached to the LC tank. This can either be a series or parallel resonant tank. The tank and coil need to be cool, so I implemented a plumbing-type design that allows me to pump water through the coil using a fountain pump.

      The resonant tank is coupled to the power source with a coupling transformer. The transformer is connected to the inverter.

      The inverter chops the DC power source at a particular frequency. This is the resonant frequency of the tank. Now, as the workpiece heats and goes through its curie point - the temperature when the metal is no longer ferromagnetic - the resonant frequency changes. The inverter needs to stay locked on as closely as possible to the current resonant frequency to achieve the fullest power. Some will do this manually, using an oscilloscope to monitor the waveforms, or using a voltmeter on the tank and tuning the frequency to the highest tank voltage. Another method is using a phase locked loop (PLL) to monitor the phase relationship of the inverter voltage and tank voltage. This is the method I use and I will discuss this in detail later on.

      Let's start with how to easily make a workcoil. We will be using frequencies in the 10s to 100s of kilohertz (kHz), so metals will conduct the current only slightly below the surface. This is the skin effect. The current depth in mm is

      Depth (mm) = 76/√(F)

      So, the wider the tubing, the lower the resistance. We also want to use tubing so we can water-cool the coil. I purchased some refrigerator 3/8" copper tubing from Home Depot. You will also need some 1/2" copper pipe and the necessary fittings so you can feed water through one end, have it circulate through the coil, and come out the other end. I have brass fittings with nipples so I can attach some tubing to my fountain pump, and a return tube to my ice water bath.

      This is the tubing I got from Home Depot.

      LC Tank: Polypropylene Film Capacitor Bank
      For my first capacitor bank I purchased my caps from Illinois Capacitor. You can also purchase them from Newark Electronics.

      The induction heater uses a workcoil as a step-down transformer. This transformer steps the voltage down, but increases the available current to the workpiece, which is the one-turn coil that completes the transformer. The magnetic flux is coupled to our workpiece. The better the coupling, the more efficient is our workcoil. The closer the workpiece is to the coil the better the energy transfer.

      This is the workcoil and tank. The capacitors are high voltage metallized power film snubbers.

      The workcoil is made from shaping the 3/8" copper tubing. I use brass compression fittings to attach it to the LC tank. The tank is made from two 1" x 3/16" thick copper bars. I drill holes in the bars to accommodate the capacitors. We need a capacitor that can handle several hundreds of amps of current. I purchased some pulse capacitors with current ratings of 14A, 3000vdc, 750vac. With 20 capacitors this is close to 300A average current. The coupling transformer fits over the copper tubing. If you look closely, you will see the fountain pump submerged in water. This pumps ice water through the tank and back out into the bucket. Water flows in from the bottom left, through the copper pipe soldered to the bus bar, through the coil, over the bank to the upper left, and through the tubing connected to the other bus bar, and out on the upper right. You should also take note where the workcoil connects with the capacitor bank. It does not connect both leads at the front end; instead, the coil connects to opposite ends. This ensures that the capacitors share an equal current load. Otherwise, if both end connected to the front, the capacitors closest to the coil would handle the brunt of current because the resistance would be the least. When you are dealing with hundreds of amps, small changes in R are significant.

      These are the bars with the holes drilled in them. The tank uses 20 capacitors, but you can use any number that gives you the capacitance and current handling capacity that you require.

      First, you need to determine what operating frequency you will use. Higher frequencies have greater skin effect (less penetration) and are good for smaller objects. Lower frequencies are better for larger objects and have greater penetration. Higher frequencies have greater switching losses, but there is less current going through the tank. I choose a frequency near 70khz and wound up with about 66khz. My capacitor bank is 4.4uf and can handle over 300A. My coil is near 1uH. The capacitors are from Illinois Capacitors. Mine are 0.22uf/3000vdc. The model number is 224PPA302KS.

      Fres = 1/2π√(LC)

      Once you wind your coil you can get an idea of its value by making a simple RLC circuit with it and connect it to a function generator and scope. I used a 1R resistor and a 500pf capacitor. I increased my function generator sine wave and measured the voltage across R. At resonance the LC impedance drops and the voltage drop across R peaks. This gave me a ballpark figure, but you can just go by the calculation.

      Now, as far as the workcoil goes you can form the workcoil by driving a piece of PVC tubing into the ground. I used a 1" pipe (1.5" OD). Take the copper tubing and fill it with sand or salt. Make sure it is completely filled. This way it will act like a solid tube and will not collapse when you bend it. Fix one end with something like a heavy vice and work the tubing around your PVC tube until you have your desired number of turns. Four to five turns at 1.5-2" will give you a coil with an inductance between 0.8 - 1.3 uH.

      You can see how nicely the coil forms around the pipe. Once you are happy with the turns and shape you can blow the sand out with an air compressor

      Xem bài viết cùng chuyên mục:

      Sửa lần cuối bởi 2012; 05-06-2012 lúc 10:28.

    2. Những thành viên đã cảm ơn 2012 vì bài viết hữu ích:

    3. #2
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      Mặc định Ðề: Nguyên lý máy hàn (tôi) cao tần.

      Power Supply: Voltage double and regulated source
      need to talk about two power supplies for the unit. One is the high voltage DC that the inverter converts to AC for feeding the tank. You need an unregulated, smoothed source. You can use 110vac through a rectifier and smoothed with a 1000uf-1500uf capacitor for a supply of 170vdc. I used a voltage multiplier to convert it to 320vdc. Below are some basic schematics for a voltage doubler. I used the third variation for mine. Make sure you have your rectifier on a large heat sink because it will be conducting a lot of amperes. My rectifier is rated for 25A/500vac.

      When I transitioned to my 10kw unit I increased the size of my high voltage supply. Each capacitor is rated for 450vdc, so I can go up to 900vdc between both ends. I use two 50A rectifiers giving me 100A.

      The second power supply you will need will be a 15vdc regulated source. It is imperitive that it is regulated because the PLL has a voltage controlled oscillator. The VCO determines the output frequency based on input voltage it receives. The frequency range it can generate is based on its supply voltage, Vss. If the supply voltage wanders, the oscillator frequency will wander and this will definitely throw you out of resonance.

      Now, when I made the 10kw unit it uses four mosfets instead of two. This is twice the amount of gate charging. You need to make sure your 15vdc supply can supply the amps to rapidly charge the gates. It should also have a robust transformer and capacitor on the end to make sure there is plenty of charge available. I plan on adding an outboard pass transistor. One problem that plagued me for the longest time was a jittery inverter current when I reached modest power levels. The current would jump back and forth when compared to the inverter voltage. It appeared as if two currents were competing. At first I thought this was EMI affecting my gate drive and I spent the longest time trying to fix it. I noticed that when I disconnected any one of the four mosfets the current tracing was perfect. This led me to believe that I was falling short on charging all the gates rapidly enough, and the mosfets were not all conducting identically. Remember, you need to fully turn the mosfets on in the shortest time possible. I put a scope on the gates and noticed that the slopes changed when I added the fourth gate. I solved the problem by adding a 39000uf capacitor to my power supply. This was with a 1.6A transformer and a 2A 15v regulator. The tracing was perfect. I plan on changing the transformer to 3A and adding adding the outboard pass transistor just to play it safe.

      Ferrite Toroids, RCL Theory and Transformer Coupling

      I guess the best way to understand what is going on is to start with the workcoil and work backwards. Remember from earlier I said that the workcoil is the primary end of a step-down transformer. We have hundreds of amps flowing through here and this creates a voltage in the workpiece. We achieve these high currents because the RCL tank is at resonance. This means that the inductive reactance and capacitive reactance cancel out, and all we are left with is the small, real resistance.

      Below we have a RCL circuit with a resistance of 4R, Zl = 4ohms and Cl = 3ohms. The reactive impedance cancels to 1ohm, giving us a phase shift of 18degrees leading. The inductor wins and the inductor voltage leads the current. There is only one current running through the series circuit. You can also say the inductor voltage leads the voltage across the resistor, because the voltage and current of the resistor are in phase. Remember, the voltage drop across an inductor is a reaction against a change in current through it. The instantaneous voltage is zero when the current is at a peak because the change in current is zero, manifested by the zero slope.

      If the inductive and capacitive reactance cancel out the phase shift is zero. The current in the circuit is in phase with the voltage.

      Now here is an important point. The maximum power transfer will occur when the current is in phase with the voltage.

      So, at resonance, the current in the series circuit is in phase with the voltage source. If we are out of resonance the current phase is shifted from zero with respect to the voltage. If there is more inductive reactance the current lags the voltage; if there is more capacitive reactance the current leads the voltage. You can also say the capacitor voltage lags the current.

      What is the voltage source for the series tank? It is our coupling transformer. I am experimenting with different materials and turns, but right now I am using an iron powered core from Amidon Corp made from Type 3 material. This material is good from frequencies between 0.05Mhz and 0.5Mhz. I used two toroids. Each is 2.25" in diameter and 0.565" thick. I wound 14g wire around for 20-26 turns. I am still trying to figure out the optimum turns and the best material. The lower the turns the greater greater the exciting voltage to the tank. However, magnetization current goes up as does the load on the inverter.

      Below are the two toroids. I use two to prevent saturation. I wonder how three would do?

      Here I have wound 14g wire around. The transformer does not impart a phase shift if place on the tank correctly. If you flip it around you will introduce a 180 degree shift which will prevent the PLL from locking onto the frequency. Just turn it around. Which way is the right way? Use the right-hand rule.

      Here is a solenoid with the current flowing in the direction shown. Put your right thumb in the direction of the current and your fingers curl in the direction of the B field. The field outside of the coil is not important to us; the field inside the solenoid sums to one large field going from right to left. If we had a metal bar or part of the toroid's arc inside, the field would travel through it.

      So here is a mock-up of the coupling transformer. The current travels to the positive terminal of our toroid transformer output. Using the right hand rule we can realize the direction of the B field for each turn. The black arrow on the toroid shows the direction the field travels in the core. Using the right-hand rule again we see that the current travels through the copper tubing from left to right towards the positive terminal of our RLC tank. We will use this as the positive lead for monitoring our tank capacitor voltage later. If you are unsure which end is which you can wind a few turns of wire as a secondary and scope the ends. The voltages in and out should be in phase.

      Ferrite Transformer

      When I started this project I didn't understand how one determined the number of turns to put on the primary coupling transformer. There are several factors to consider. First, the wire needs to be able to handle the current. If you are dealing with high frequencies, the majority of the current is conducted on the surface. This is the skin effect. You will need to have several insulated strands to increase the surface area; these strands will need to be twisted in order to reduce eddy currents. As you pack more wire into the space, heating becomes more significant. If your wire is not robust enough you might need a cooling system.

      The power to your system has a voltage and a current. If you have the means to run high voltages, you can adjust your windings to keep the primary current low enough to reduce the heating of your transformer and switches. If I want to keep the primary current low I need more turns on the primary. As long as I have enough voltage, the same primary current will yield a much larger secondary current. Let's go over an example:

      My transformer has 10 turns on the primary and one on the secondary (this is the resonant tank). Let's assume that the load across the secondary is 1 ohm. If I have 100v on the primary, a 10:1 transformer gives us 10v on the secondary. 10A of secondary current requires 1A of primary current. The power draw is 100W. If I want to draw less current I can wind a 20:1 transformer. Now, 200v on the primary results in 10v on the secondary. The current is still 10A on the secondary, but it is 0.5A on the primary. This means that as long as I have a higher voltage supply, I can reduce the current my inverter requires, and still maintain the same power to my workpiece. If I have 400v available, I can draw the same 1A on the primary, but have 20A available on the secondary.

      When heating small pieces of metal with small coils, the current demand will go up quickly as there is little material to quench the tank. You want a lot of turns on the primary in order to keep the current draw low while still supplying a lot of current to the tank. If you plan on heating large pieces of metal, the tank gets quenched and the current draw will be too low for effective heating. You need less turns on the primary in order to provide a higher excitation voltage to the tank.

      Let's look at another example where the workpiece is quenching the tank. In this case you don't have enough voltage to get an adequate current to flow in the tank. If you have 200v on a 20:1 transformer you will have 10v on the secondary. If the load is 1R you will have 10A on the secondary and 0.5A in the primary. If our maximum voltage is 200v we need to draw more current, making sure our switches can handle this of course. By changing to a 10:1 transformer we get 20v @ 20A on the secondary; the primary we have 200v @ 2A. We are drawing more power and we have doubled the output current at the expense of needing to deal with four times the primary current. As long as the primary circuit can handle this we have solved the problem. As you go lower on the turns you need to make sure you do not saturate the core. Also remember that a small amount of the total primary current is magnetization current.
      Oscilloscope Tracings
      The inverter outputs a drive voltage to the coupling transformer. The current in is in phase with the current out. When the tank is at resonance, the tank current is in phase with the drive current of the coupling transformer, and is in phase with the inverter input voltage. If anything, you want the current to slightly lag the voltage because the mosfets behave better when facing an inductive, rather than a capacitive, load. This has to do with the mosfets conducting in the reverse direction. The tracing below is clean and allows me to reach very high power levels while maintaining relatively cool mosfets.

      Now, if the tanks is above resonance we have more inductive reactance. The tank's net current will lag the driving voltage from the coupling transformer. Since the input and output current of the coupling transformer are in phase, the tank's current is lagging the inverter driving voltage. Below you can see the dominating inductive reactance results in the inverter current (triangle-looking wave) is almost 90 degrees lagging the inverter voltage (square wave).

      If we are below the resonant frequency capacitive reactance results in the current leading the inverter voltage. Also, there is ringing in the current waveform and at the inverter voltage transitions. This noise gets worse with higher power levels and can result in mosfet failure.

      Below is another example of ringing. You can see ringing on the voltage at the transition and on the current waveform. I have positioned them apart for easier viewing. This is due to high inductance on the gate. Heavy current on the gate causes a large Ldi/dt. The problem can usually be solved by either increasing the gate resistance (increase the resistor value), or decrease the stray inductance by shortening the gate lead. I was able to almost eliminate the ringing by shortening the gate lead, but then I did not have enough length for connecting two in parallel. So I changed the value of R from 5 ohms to 10 ohms. The first image is with the 5 ohm gate resistor. I was still able to charge the gate with 10 ohms in a sufficiently short amount of time at 15v.

      These images show the waveform after the fix: shortening the gate leads as much as possible to still allow room for paralleling two of them and increasing the gate resistor from 5R to 10R. Notice the clean voltage square wave and the smooth current curve. The second image is a blow-up of the first.

      Below is a basic sketch of the half-bridge inverter. The coil in the middle is the coupling transformer to the resonant tank. The arrows show the paths the current takes as the switches alternate between closed-open and open-closed.

      Below are two sketches. Sketch I shows ringing if there is too long of a delay during switching. If the next switch does not close in time, the inductive kick will drive the voltage too high, causing an overshoot, followed by a large dip when it finally closes. Sketch II shows profound voltage sagging in the middle of the waveform. I had this happen when the decoupling capacitors went bad, shorting the current path. The capacitors are needed to remove any DC component from the pulse.

      I would like just mention that the inductive waveforms is really an exponential curve. If we can approximate the tank above resonane as a RL circuit responding to a step response

      The solution to


      Analysis of a capacitor dominant RC circuit will yield something similar. When dealing with a RCL step response one has

      and the 2nd order differential equation is

      and the general solution is

      If the system is underdamped the solution has the form:
      V(t) = e-αt(Bcos(ѡt) + Bsin(ѡt))

    4. #3
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      Mặc định Ðề: Nguyên lý máy hàn (tôi) cao tần.

      Oscilloscope Tracings II
      Let's continue our discussion of oscilloscope tracings so we can better understand how the inverter is going to work and lock onto resonance. From the last page I mentioned that voltage across the tank capacitor lags the current by 90 degrees. At resonance, the tank current has a zero phase shift with respect to source (inverter) tank voltage because the inductive and capacitive reactance cancel out. If you display the inverter voltage and capacitor voltage together, you can see the sinusoidal capacitor voltage lags the inverter voltage by 90 degrees. The square wave is the inverter voltage, but you would get the same relationship if you scoped the voltage output of the toroid transformer.

      We will monitor this relationship. We are at resonance when our PLL chip keeps Vc ninety degrees lagging behind Vinverter. Now, we can easily exceed the chips maximum input voltage, so we need to clip the top and bottom the the capacitor voltage, and keep it to a maximum of 15v. We do this with some clamping diodes yeilding this waveform, which will be the signalin input on pin 14 of the HEF4046.

      Below is a diagram of the scoped voltages. Using a differential probe, the positive lead goes to the positive inverter lead going to the toroid and the negative to the negative lead. Using a second differential probe we scope the + and - ends of the capacitor tank. Vc will lag Vinv or Vtank. We will have to invert the Vc waveform, that is shift it 180 degrees, in order for the PLL to work, which I will discuss shortly.

      Now, we are ready to talk about the phase locked loop chip - the HEF4046. After this discussion, we will have enough information to understand the workings of the inverter and how it maintains a lock on the resonance.
      Oscilloscope Tracings III
      I have to share some bad waveforms I got one day. I hadn't used my heater all summer and wanted to try it out before giving it to a friend. Below are the voltage/current waveform. Underneath is a tracing of the gate drive signal and the inverter voltage from another run. Notice how the current is no longer a nice sinusoid. The negative current prematurely starts to rise and then go back down before resuming its normal cycle.

      Here is another image. The waveform is different from above, but still bizarre and not a good sinusoid.

      This is the inverter voltage (yellow) and gate drive (blue). Notice how the voltage heavily sags and the gate signal is no longer a clean square wave.

      Here is another gate wave that is abnormal taken at a different time.

      As you can see, I was getting strange waveforms and I did not know why.

      At first I thought it was the mosfets so I swapped them out. When that failed to fix the problem I redid the gate resistors and shielding. Then, I pulled out the inverter capacitors and replaced them. Still no good. Frustrated, I took out the board and replaced the gate drive capacitors. When this failed I redid the entire circuit board thinking I was getting some type of cross-talk or a failed component. I saved myself from buying another tank capacitor by connecting the coupling transformer to another LC tank. Again, I had the same problem.

      I thought I checked everything and I couldn't understand how the waveform had deteriorated. Sometimes, the current appeared to go at twice the frequency of the inverter voltage. Then, I had a final thought. I started looking at my high voltage DC supply. I must have reconnected the HV wires to the inverter early in the summer. Notice in the picture how they are not together.

      They should be together to cancel out any stray inductance as shown below.

      Amazingly, after days of racking my brain, this simple solution was all that was needed. I twisted the HV wires close (as I had done in the past) and made sure they were close on my inverter board before splitting to each of the HV rails. At the frequency I am driving my coil, stray inductance and capacitance on the HV lines is significant and clearly affected my waveforms. Not only did this affect the LC tank, but it affected the gate signal and the voltage supply signal to the circuitry, making things even worse. Hopefully, my experience will make someone's life easier if these symptoms appear.

      Below are the waveforms for the inverter voltage and current immediately after this repair. I have the frequency deliberately higher than resonance to prevent reverse currents.

      Below is the gate signal after this repair.

    5. #4
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      Mặc định Ðề: Nguyên lý máy hàn (tôi) cao tần.

      Phase Locked Loop (PLL) Basics
      When you read about induction heaters and inverters you will probably come across the term phase locked loop. The people writing the tutorials will assume you know all about these. I will make the opposite assumption and give you a brief understanding of the concept so you can understand how this will help maintain resonance with our induction heater.

      A PLL consists of three parts: a voltage controlled oscillator (VCO), a loop filter and a phase detector. The VCOout drives the device, or inverter gate in our case. It also closes the loop by feeding itself back into the phase detector so it can get compared with a reference signal.

      The VCO generates a 50% duty cycle square wave; the frequency depends on the input voltage to the VCO. The higher the VCOinput (pin 9) voltage the higher the VCOoutput frequency; the lower the voltage the lower the frequency. The PLL phase detector compares the phases of two inputs: the reference signal on pin 14 and the VCOout frequency. The phase detector has two options for outputs: PCA1 and PCA2. We use the former, which is a XOR gate.

      The logic is high if one of the two inputs is high; otherwise it is low. It will generate a square wave whose width is based on the phase difference of the two signals. If the two waves are 90 degrees out of phase the average value of Vphi is Vdd/2. The loop filter takes the phase detector output and converts this to the input voltage to the VCO. The simplest filter is a RC low-pass filter. The cut-off frequency will determine how sensitive the PLL is to phase changes, and how well it stays locked on the reference signal.

      So what happens? At resonance the tank current is real and in phase with the coupler transformer voltage, which is in phase with the inverter voltage. The tank capacitor voltage lags the tank current by 90 degrees; therefore, it lags the inverter voltage by 90 degrees. Now as the workpiece heats its ferromagnetic properties change. The workcoil becomes a variable inductor and affects the resonant frequency of the tank. If the effective resonance goes down, it seems to the circuit that we increased on drive frequency to the tank. This makes the tank more inductive. Inductance causes the source voltage lead the tank current. That is, the tank current is forced to lag the inverter voltage. The capacitor voltage initially lagged the current by 90 degrees. This means the capacitor voltage lags the inverter voltage even more as shown below.

      Figure 3

      Below we can see the relationships with Vinv, Vcap and Vphi. Vphi is high Vinv or Vcap is high, but not both.

      Figure 4

      The top shows Vinv and Vc. An increase in inductive reactance is the same as if we increased our inverter drive frequency. We lower it by decreasing the voltage to VCOin. We see in the top pair that as Vc shifts more to the right of Vinv the XOR region increases. However, we need it to decrease in order to yield a lower voltage for VCO. We achieve this by inverting Vc to Vc_inverted. Now as Vc_inverted shifts to the right, Vphi decreases. We integrate this to a voltage value and use this for VCOin. A smaller VCOin results in a lower frequency and we stay in resonance. The frequency range is determined by resistors on pins 11 and 12 of the PLL. When, VCOin is at ground the frequency is at the low-end of the range; when it is at the supply voltage it is at the high end.

      When we are at resonance - inverter voltage and current are in phase - the inverter voltage leads the tank capacitor voltage by 90 degrees. Vphi is half of half a pulse width (see Figure 2 and 4). The average voltage is Vdd/2, or 7.5v if our supply is 15v. So, 7.5v at VCOin will keep us close to resonance if our center frequency is Fres. The problem is that Fres changes with different workpieces and during heating. However, the PLL will adjust itselft to maintain a lock on the phase relationship.

      The scope images below show these waveforms. The first picture is at a lower frequency than the bottom picture. Shown are Vcap_inverted, Vinv, and Vphi. The capacitor voltage is clipped to protect the PLL chip.

      The capacitor voltage is a clean signal, and was distorted when I tried to show three signals. Below is just the inverter and tank capacitor voltage.

      We need to discuss a few more things about the PLL next.

      Phase Locked Loop (PLL) Basics II

      If you will recall, here is a block diagram of the PLL device.

      There are several filters one can use for the feedback loop. The simplest is the passive low-pass RC filter. I used the active integrator, which use a R and C element. To ensure a DC bias does not work itself into the capacitor, I put a discharge resistor in parallel with C. The active filter has more gain than the passive filter. The phase shift in the beginning is -90. I don't know if this helps keep our signals at -90 or not. I scoped both the passive and active filter action by monitoring the relationship of the inverter voltage and current, and I can say that the latter maintained a tighter lock on a -90 phase difference during changes in the tank's resonant frequency. Below is a table of some filters. I used one similar to the second. I add a variable voltge input to V- on the op-amp, which allows me to fine tune the frequency. I usually tune it slightly above resonance, using a voltage monitor on the tank voltage for the near-high point. One other thing: you need a gain of -1 after the active filter because it inverts the signal. The -1 gain op-amp will restore the proper polarity.

      Let's talk about how we set the free-running PLL frequency and the range it can capture. If the resonant frequency falls with the PLL capture range, the PLL will be able to find the frequency that maintains the 90 degree shift that we want, and maintain this phase lock as the frequency required for this phase difference changes over a wider range of frequencies.

      Here is the chip

      These forumulas can be off and require constants as shown below:

      You can also use graphs on the manufacturer datasheets to get you in the ballpark for the values you need. The first step is to determine the capacitor value that will get you near your Fres at a given Vdd voltage. Determine the R value you need for Fmin, and then determine the R you need for Fmax.

      Let's do a quick example. My Fres is 65kHz and my supply is 15v. Actually, my supply is 14.4v, because I have a diode to protect from hooking up the pos and neg in reverse. I go up the left hand side to the 60khz row and across to the 15v supply line. I go straigtht down and get a C1 of 300pf. This will be my starting point for my equations. Using C1 = 330pf, I will pick some R values and measure the actual frequency in order to determine the values of the constants K1 and K2.

      We want to have the center frequency, (Fmin + Fmax)/2, equal our resonant frequency, and we want about 10-15kHz on either side. Now, the chips can vary from the equation by a factor of 4, so you need to multiply each equation by a constant. Take a 100k resistor for R2 and R1. Ground pin 9 and measure Fmin. Next, connect pin 9 to Vdd and measure Fmax. This will give you K1 and K2. I measured 50kHz for Fmin, giving me a K1 of 1.81. I then connected pin 9 to Vdd and got 154khz. Subtracing Fmin, 50khz, I was able to dedue that K2 equals 3.78. My frequency is 65kHz, so I want something between 50-80kHz. I will use a 330pf capacitor, as determined from the graph, and values of K1 = 1.81 and K2 = 3.78. I now use these values to determine the true values of R1 and R2 that I need, which is 100k and 348k. The calculations are below. Of course, you need to verify this with your scope.

      Fmin = 50khz = 1.81/(100,000 x 362e-12)

      Fmax = 80khz = 50khz + 3.78/(348,000 x 362e-12)

      On my circuit I add a trim pot and another resistor in parallel to R2 with an optional jumper. This gives me a selection of resonant frequency ranges.

      So, how does our circuit come together? Let's see.
      Induction Heater Inverter Schematic
      Most of the electronics components on the schematic are from Digikey Corp and Mouser Electronics.


      The PLL receives two inputs through pins 14 and 9. Pin 14 is the clamped capacitor tank voltage. It is inverter (shifted 180 degrees) in order for the feedback to work properly. The high voltages are kept down with R1. All inverter grounds are isolated from earth ground. C7 and resistors on pins 11 and 12 set the capture range. Jumper JP1 converts pin 12's resistor from 100k to 60k. R5 affords you the ability to vary the capture range even more for tuning the center frequency to the tank resonant frequency. We will discuss this at the end.

      PCAout goes through the active integrator filter, which is made up of a quad op-amp. The integrator output then goes through a filter with a gain of -1 to restore the polarity of the signal. During use, jumper JP2 is open and JP3 is closed to allow the feedback to get to pin 9. The drive frequency leaves pin 4 and drives a non-inverting and inverting gate drive. These chips drive the primary of a 11 gate drive transformer, T1. C1 removes DC bias. Diodes D5 and D6 offer some delay so both mosfets are not on at the same time. These series diodes have nothing to do with reverse currents, like the one's you are used to seeing across the DS juntion. Again, they are for timing. Your tracings should be short to the gate drive on the mosfet. I have connectors on my board going to wires which run to the chips on large heat sinks. The wire acts like an antenna and you can get noise which will induce wild oscillations in your mosfets, destroying them. I put a ferrite bead that attenutes frequencies above 300khz right before the lead to the gate drive. This works perfectly. Below are the tracings going to the gates and then showing the tracing from one of the gates and the inverter output.


      These are the gates drive signals going to the mosfets. The signals are superimposed. The small slope is part of the delay imparted by the series diodes D5 and D6.

      This is the inverter tracing on top, and one of the gate drive signals on the bottom. With this mosfet, when the gate is high the DS junction grounds the power, so the voltage drops to zero.

      Below is the timing showing ZVS. The voltage goes through zero volts exactly when the current is zero.

      Below, one of the series diodes is shorted, so we can compare the timing of the signal going to both gates. The bottom tracing has the transformer gate drive going directly to the gate. The tracing above it goes through the diode The temporal difference between the gate drive with and without the series diode is close to 100ns.

      Below are the gate drive waveforms with both series diodes working.

      Below, both series diodes are shorted, and we can see the time to reach the same voltage is delayed by about 200ns.


      The op-amp is centered around Vdd/2. R10 moves the center point on the integrator allowing you to fine tune PLL frequency. You can force it to stay a little above resonance by adjusting it. When connecting it to the circuit, set it up so clockwise motion increases the PLL frequency.


      Mosfets U1 and U2 have ultra-fast diodes across the source and drain to protect the slower acting intrinsic drain diodes. There are no series isolation diodes with the mosfets for two reasons. We are doing zero volt/current switching which is guarenteed when the circuit is in tune by the PLL. When we switch the mosfet there is no current or voltage on the device. Secondly, the present day mosfets have very fast intrinsic diodes, rated for flywheel service. Capacitors C1 and C2 set a point half-way above ground, which gets charged when U1 is open, and discharges to ground when U1 closes and U2 opens. The current transformer T2 uses a 1:100T ratio to monitor the inverter current. The 100R resistor means that every 1V on the oscilloscope is 1A of current going to the coupling transformer.

      Now, let's look at the tank circuit schematic. The inverter output is coupled to the tank through T3, which is a 20:1 toroid transformer. The 20 turn primary is connected to the inverter output. The coper tubing which form the connects for workcoil and capacitor serves as a one-turn primary. You can experiment with different toroid materials and turn-ratios. The resonant frequency will changes as the material goes through its curie point.

      Below is a picture of the current conduction through the inverter during different phases of the power transfer cycle. It shows how the free-wheeling diodes come into play to divert the reverse current around the mosfet.

      During Mode 1, the upper mosfet is conducting and transfering power to the resonant tank through the coupling transformer in our circuit. In Mode 2, the mosfets are transitioning, and the upper mosfet turns off slightly before the bottom one turns on. Here, current is conducted through the free-wheeling diode of the lower mosfet. In Mode 3, the lower mosfet turns on, and the resonant tank throws the power back through mosfet. In Mode 3, both mosfets are off during the transition, and the upper mosfet's free-wheeling diode conducts the current.


      You will have to tune the PLL to your tank's resonant frequency. To do this just connect jumper JP2. Leave jumper JP3 open, which goes to the integrator. With a volt meter, measure the voltage at pin 9 and the inverter ground. Trim R6 until you have one half of your supply voltage. Accounting for the diode voltage drop on the regulated 15vdc supply, this should be around 7.2v. You will need a differential set of oscilloscope probes to do this next part right. Put one probe pair across the current transformer, which would be across R15. Put another probe pair across the inverter output at J2. This will monitor inverter voltage and current. Using a variac, set the voltage input to your inverter high voltage supply to a low value like 30-40vac. Trim R5 until you have the current and voltage in phase. A cruder method uses an unregulated rectifier with a smoothing capacitor with the voltage input being the tank capacitor. Monitor the voltage for a maximum.

      Once you are confident that the PLL's center frequency is close to the resonant frequency, open jumper JP2 and close jumper JP3. Turn on the inverter first and then turn on the variac to the voltage doubler, which provides the high voltage for the inverter. Slowly increase the voltage while monitoring the inverter voltage and current waveforms. After 20 or 30v you should see it lock onto Fres. The inverter output will be a nice square wave and the current will be close to a smooth sinusoidal tracing. If all you see is a triangle-looking wave for the current you probably have the polarity wrong on your capacitor voltage input to pin 14. The quickest fix is to swap the connections going to the coupling transformer. Try it again and it should work.


    6. #5
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      Cảm ơn
      Được cảm ơn 568 lần, trong 397 bài

      Mặc định Ðề: Nguyên lý máy hàn (tôi) cao tần.

      Một số hình ảnh về board

      Induction Heater Levitation Tutorial
      Induction heating and levitation is pretty cool. Using a levitation coil, you levitate a conductive object in the magnetic field and heat within that field. Depending on the metal and power setting you can even boil it mid-air. Aluminum will levitate and melt easily at 1-1.5kw of input power. You can levitate copper and steel balls. You can even melt them; however, solid balls were too dense at my 2.5kw power level. In order to melt solid copper and steel you need near 8kw of power; suspending molten copper and steel requires over 10kw of power. Component heating can be an issue so you need to make sure you have a robust cooling system for the mosfets, igbts, diodes, transformer and coil.

      Current going through the coil sets up a magnetic field. This field, according to Lenz's law, sets up an opposite magnetic field in the workpiece. This magnetic field opposes the one inducing it, and repels the object upwards. The picture below shows a snapshot in time. The field alternates. The coil also increases in diameter as one moves upwards. This results in there being a magnetic force underneath the object, but nothing directly above it. This results in an upwards force. The object moves up until the distance of the workpiece to the inner surface of the coil is such that the magnetic field is too weak to drive it up any more. The bucking plate at the top turns in the opposite direction. The two fields cancel out so there is no upward driving force at this point. It is a null zone.

      Now, the magnetic field created in the workpiece creates circulating eddy currents. These currents heat the workpiece. The closer the workpiece gets to the coil the better the coupling, which creates more heating. You will find if you gently push the object down with a quartz rod it will heat up very quickly.

      Below are some diagrams showing what was just discussed.

      Below are the pictures of the levitation coil. The turns are tight, so you will need to use sand or salt so you can bend it without deforming the tubular shape. The coil is a conical helix. The bottom has a smaller inner diameter than the top. Make a bow to reverse the direction and turn 1-2.5 coils in the opposite direction for the bucking plate. Keep the coil tight, but make sure the coils don't short. You will need a quartz rod to hold the object in place until it levitates, or while it is heating. This is one levitation coil that I made. I made another one that is slightly larger. When I am levitating dense metals I keep the bucking plate further from the main coil to minimize the downward forces on the workpiece.

      Tất cả các bài trên được lấy từ nguồn (http://www.mindchallenger.com/inductionheater/)

    7. The Following 3 Users Say Thank You to 2012 For This Useful Post:

    8. #6
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      Địa chỉ
      Hanoi University of Science and Technology
      Bài viết
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      Được cảm ơn 1,495 lần, trong 565 bài

      Mặc định Ðề: Nguyên lý máy hàn (tôi) cao tần.

      BH sắp cần vài kiến thức liên quan đến cái này. Cảm ơn bạn.
      TB: nhìn mấy con oscilloscope thích quá.

    9. #7
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      Mặc định Ðề: Nguyên lý máy hàn (tôi) cao tần.

      vì sao bài này dc lên "Chú ý vậy" ?

    10. #8
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      Được cảm ơn 568 lần, trong 397 bài

      Mặc định Ðề: Nguyên lý máy hàn (tôi) cao tần.

      Trích dẫn Gửi bởi aladanh2000 Xem bài viết
      vì sao bài này dc lên "Chú ý vậy" ?
      Pác soi kinh thế em kéo lên cho dễ nhìn

    11. #9
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      Được cảm ơn 568 lần, trong 397 bài

      Mặc định Ðề: Nguyên lý máy hàn (tôi) cao tần.

      Tài liệu máy hàn ống thép cao tần
      Minh họa quá trình sản xuất ống thép.

      Một phần không thể thiếu trong các dây chuyền sản xuất ống thép là động cơ truyền động . động cơ DC được sử dụng với ưu điểm điều chỉnh tốc độ và khả năng quá tải lớn.

      590 Series DC motor ( điều khiển 4 góc phần tư , có hãm tái sinh.)
      Bộ điều khiển động cơ một chiều DC590+ Integrator Series 2 đáp ứng được hầu hết các yêu cầu ứng dụng phức tạp.
      Bộ vi xử lý 32 - Bit, lập trình theo các khối chức năng (Function Block Programming), các ngõ vào ra I/O được cấu hình bởi người dùng ,tối ưu hóa các yêu cầu tính toán, xử lý số liệu.

      DC590+ tương thích với các chuẩn truyền thông phổ biến trong công nghiệp như Ethernet, Profibus, ControlNet, DeviceNet and CANopen,cho phép dễ dàng kết nối linh hoạt với các thiết bị công nghiệp khác hay điều khiển một hệ thống tích hợp gồm nhiều động cơ bằng cách kết nối nhiều bộ DC590+ với nhau.

      DC590+ được lập trình bằng phần mềm DSE Lite- phần mềm dùng chung cho các bộ điều khiển thông minh của hãng Parker như AC690+, AC 890.., Rất đơn giản cho việc cấu hình, cài đặt tham số, giám sát hoạt động, chẩn đoán lỗi.... DSE Lite được cung cấp miễn phí cho người dùng.

      ỨNG DỤNG

      ►Điều khiển Thu cuộn (Winder), Xả cuộn (Unwinder)

      ►Điều khiển Lực căng ( Tension)

      ►Đáp ứng tất cả các yêu cầu ứng dụng điều khiển động cơ DC


      ►Speed Control

      ►Torque Control
      Tài liệu cài đặt nhanh.

      I. Function introduction
      II. Istruction of wiring terminal
      II. Istruction of operating panel
      IV. Parameter setting
      V. Faults disposal
      VI. Electric principle diagram

      I. Function introduction
      590 Series DC motor speed regulator.
      The 590 serires TNC reversible DC speed regulator made by Eurotherm Drives Ltd used for the control of separate excitation motor and permanent motor. Motor armature control device is regenerative control device and four quadrant operating, composed of total control thyriostor and advanced electronic control device,it can control speed acceleration ,deceleration and torque in two rotating derections. Field regulator is composed of single phase full wave half control thyristor bridge with instantaneous over load protection. The control circuit can receive power frequency in 40~70Hz through auto regulation, it has anti interference function. Armature control decice is not affected by phase sequence rotation.
      There is a LCD screen on up-left panel of speed regulator to display operating state, parameters and faults type.
      There are four buttons on the right of screen for parameters setting, amendment, selection etc.
      There are six indicating lamps on the right of screen to indicate current working states.
      Lots of wiring terminals on upper and lower sides of regulator are signal input and output terminals.
      Technical contents: control circuit and power circuit wholly separate. Control function is TNC advanced PI (propotional integration) regulation. It can reach the perfect dynamic performance with its current loop.
      Protection functions: field fault, speed feedback fault, thyristor compound, thyristor trigger circuit fault, transfer protection, over current.
      Diagnosis function: computer TNC, latch the original fault, display automaticly, light-emitting diode circuit state displaying.
      Working temperature: 0℃~ +55℃
      Moisture: Max. 85% rated moisture
      Environment: nonflammable, uncondensable.

      II. Istruction of wiring terminal

      2.1. L1,L2,L3: terminals, on the most bottom(right side) of regulator, 3 phase AC input, 380V, euip rapidity fuse as its peripheral protection device, connect to the secondary side of regulating transformer
      2.2 A+,A-: terminals, on the most bottom(left side) of regulator, DC output, connect to motor armature, the control signal decides the positive or negative of the terminals output current and positive rotation or reverse rotation of the motor.
      2.3. D3,D4: upper side of regulator, field current output side, connect to DC motor field wires(LC1,LC2).
      2.4. D5,D6: upper side of regulator, control side of main contactor, connect to main contactor wires (JC1,JC2).
      2.5. D7,D8: control (auxiliary) power input side, provides power source to regulator, AC 220V(D7 to earth line N, D8 to heat line ), open lower gate of regulator, there are 3 green modular A,B,C and everyone have 10ps, A1-A10,B1-B10,C1-C10.
      Terminal explain:
      ⑴ A1(AGND0V):for public reference.
      ⑵ A4(TSGD):speed given inout, effective voltage: -10V to +10V, motor rotation: pocitivemax.to reverse positive max.
      ⑶ A6:max limit inout, max output current is 200% of rated value connecting to B3(+10V).
      ⑷ G1,G2:AC anolog velmeter input, max input voltage: 220V
      ⑸ G3,G4:DC anolog velmeter input, max input voltage: 220V
      ⑹ B3:+10 V input, max output current: 10mA, short circuit protection.
      ⑺ B4:+10 V input, max output current: 10mA, short circuit protection.
      ⑻ B5(LSJC):zero value speed signal output, output is +24 V when motor speed is zero, output is zero when speed is not zero.
      ⑼ B6: fault output, output is 24V in normal, zero in fault.
      ⑽ B7:speed ready output, output is +24 when main contactor couples, 3 phase,output field current and other aspects are normal, otherwise, output is 0.
      ⑾ B8,B9:urgent stop control. Regulator works normally when them connect ot C9(+24V), otherwise, regulator will stop.
      ⑿ C1(AGND):reference voltage 0V
      ⒀ C2:motor heat protection input, can connect to heat protection breaker, when C2 displays 0Vmeaning normal state, break off means over heat.
      ⒁ C3(STA):main contactor coupling control, connecting to C9, D5,D6 will output 220V voltage making main contactor coupling,check whether 3 phase power is normal, then, regulator will output field current automatically, and check whether field current is normal. If it is normal, B6 is +24V, otherwise will be 0 V, break off with C9, mian contactor will be off, field current will disappear.
      ⒂ C5(ENA):regulator start input, break off with C9(+24V),DC output (A+,A-)will be 0, connect to C9 , speed of motor will vary with given voltage. Means that motor trip control will be step with this signal in normal status.
      ⒃ C9:+24V output,provides control signals to power.

      III. Istruction of operating panel
      3 .1.instruction of indicating lamp
      Health----------------stop for fault
      Run-------------------havent work
      Start Contactor------havent coupled
      Over current Trip---over current trip protection
      Program stop--------urgent stop
      Coast Stop----------- urgent stop
      All lamps should light in normal working.
      3.2.Instruction of LCD screen
      LCD screen is used to display the current operating statem paramenter and fault reason.
      ⑴ normal working: “DIGTIAL DC DRIVER MAIN MENEU”
      Faulting, regulator will cut off contacor, and display “****ALARM******” in first line.
      ⑵dislpay fault catogeries in second line
      Stop machine first and then press main loop stop button, regulator can reset, check out the reason and restart.
      3.3. Function buttons
      “E” ----exsit
      3.4. Parameter control board

      Velometer pattern normal board
      Velometer input:
      ⑴IACAL armature current set with 3 rotating switches arranging to 3 numeral.
      ⑵IFCAL field current set with3 rotating switches arranging to 3 numeral.
      ⑶VACAL armature voltage set with 4 numeral switches, unit is V(VACAL is 220V)
      Switch Armature Volts Va(Volts) armature voltage Va
      150 175 200 225 250 275 300 325 350 375 400 425 450 475 500 525
      1 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0
      2 1 1 0 0 1 1 0 0 1 1 0 0 1 1 0 0
      3 1 1 1 1 0 0 0 0 1 1 1 1 0 0 0 0
      4 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0
      Note:Switch“1”---- on ,“0”----off
      ⑷ speed regulating feed back voltage setting: AC feedback use G1and G2, switch is on AC. DC feedback use G3 and G4, switch is on DC.feed back checking voltage use 2 pieces of 10 branches. Switches are unit’s order and tens place, switch tens place with 1 branch, unit’s order choice 0. tens place order choice1, the min setting value is 10V. feed back voltage the above diagram is 62V, the actural principle is settin voltage/ max feedback voltage=1.1-1.25.

      IV. Parameter setting
      4.1 Menu configuration
      Power control source( auxiliary power source D7 connect to N, D8 connect to C). display the following firstly:
      Then, the second line will be :MENU LEVEL
      Press “M”, displaying
      Press “↑”or “↓”,displaying
      Press “E” back to original status,press “M” to the next 。

      4.2 Dianostics
      Press“M” button, display the following
      Press “↑”or “↓”,the second line display the following:
      NE I CLAMP
      ANIN 1(A2)
      ANIN 2(A3)
      ANIN 3(A4)
      ANIN 4(A5)
      ANIN 5(A6)
      ANOUT 1(A7)
      ANOUT 2(A8)
      START (C3)
      DIGIN 1 (C6)
      DIGIN 2 (C7)
      DIGIN 3 (C8)
      DIGOUT 1(B5)
      DIGOUT 2(B6)
      DIGOUT 3(B7)
      BACK EMF
      TACH INPUT (B2)

      4.3parameters setting process
      Displaying “SETUP PARAMETERS”, press“M”
      ⑴ RAMPS press “M” display :
      Press “M”,display
      Press “E” ,display
      Press “↓”,display
      ②RAMP DECEL TIME , be same to the above
      ③RAMP HOLD
      ⑤%S- RAMP
      ⑩MIN SPEED
      ⑵ AUX I/O
      press“↓” , display
      ⑶ JOG/SLACK
      Press “↓”,dislpay
      ⑥MIN VALUE
      ⑦MAX VALUE
      Press “↓”,display
      INT GAIN
      EMF LEAD
      EMF LAG
      EMF GAIN
      Press “↓”,display
      ⑻ STOP RATES
      Press “↓”,display
      ○11FIELD I CAL
      ②5703RVC ERROP
      ③PROP GAIN
      ④INT GAIN
      ⑩POS I CLAMP
      ○11NEG I CLAMP
      ⑿ SPEED LOOP
      ①PROP GAIN
      Note :press “↑”or “↓” to choose feed mode
      Note :press “↑”or “↓” for choice
      1 (relate to speed )
      2 (relate to speed error)
      3 (relate to current setting)
      B、SPD BRK1 LOW
      ○13MAX DEMAND
      ○14 MIN DEMAND

      Press “M” when the second line display PASSWORD,then ,indicate
      Press “↑”or “↓”, the second line display :

      5.Alarm status
      Press “M”when the second line display ALARM STATUS, and then display:
      Press “↑”or “↓”, the second line display :

      6. parameters store
      Press “E”back to MENU LEVEL after finishing parameters setting,,press“↑”or “↓”button
      Press “M” displaying PARAMETER SAVE in the second line , then display:
      Press “↑” displaying SAVING in the second line
      Then display :FINISHED
      Press “E”back to
      Power machine to work.

      V.Faults disposal
      5.1 3 phase faults
      Controler will monitor 23 phase power on L1,L2,L3 timely. 3 phase power alarm will start if fault exsist in coupling status.
      5.2 filed faults
      This alarm will be start if the field current lower 6% rated value or controlvoltage ecrese to 50 mA or misoperation.
      Field open circuit often make the motor fault alarm. Check motor wiring and measure resistance.
      Over current alarm:regulator shall check the current whether exeed the standard 120% in field current control mode, regulator fault or control loop unbalance will cause alarm, can not set overcurrent in voltage control.
      5.3 Overcureet trip
      ⑴Motro fault
      Check resister of motor armature with megameter.
      ⑵Controller fault
      590 faults may cause current trip. For example, main processor fault, hardware current trip will make main contactor release, protective input power will cutoff from control; defective current turning will also cause armature over current trip.
      5.4. speed feedback fault
      If the D-value of speed feed and armature feed exceed setted speed feed alarm level in normal menu, or speed feed is not exceed 10% max voltage, or the polarity in rotating deviece terminal G3 G4 is wrong,larm will work.
      5.5. over voltage alarm
      If armature voltage exeed rated voltage 120%, alarm will work.
      5.6.lockedrator fault
      When motor is in lockedrotor, alarm will work,the reason is overload.
      (Note: Indication and disposal of all faults check to LCD instruction.)

      VI. Electric principle diagram
      Mạch động lực

      Mạch điều khiển
      Sửa lần cuối bởi 2012; 07-06-2012 lúc 10:46.

    12. Những thành viên đã cảm ơn 2012 vì bài viết hữu ích:

    13. #10
      Tham gia
      Bài viết
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      Được cảm ơn 18 lần, trong 15 bài

      Mặc định Ðề: Nguyên lý máy hàn (tôi) cao tần.

      Em tự hỏi cái "Induction Heater "điện áp băm cao như vậy thì khi nó làm việc làm sao có thể giải nhiệt bằng cách bơm nước vào workcoil được ạ

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